Complete question is;
Jason works for a moving company. A 75 kg wooden crate is sitting on the wooden ramp of his truck; the ramp is angled at 11°.
What is the magnitude of the force, directed parallel to the ramp, that he needs to exert on the crate to get it to start moving UP the ramp?
Answer:
F = 501.5 N
Explanation:
We are given;
Mass of wooden crate; m = 75 kg
Angle of ramp; θ = 11°
Now, for the wooden crate to slide upwards, it means that the force of friction would be acting in an opposite to the slide along the inclined plane. Thus, the force will be given by;
F = mgsin θ + μmg cos θ
From online values, coefficient of friction between wooden surfaces is μ = 0.5
Thus;
F = (75 × 9.81 × sin 11) + (0.5 × 75 × 9.81 × cos 11)
F = 501.5 N
Answer:
Danny hits the water with kinetic energy of 5000 J.
Explanation:
Given that,
The Weight of Danny Diver,
F = 500 N
m*g= 500 N
He steps off a diving board 10 m above the water.
h=10 m
when Danny diver hits water he generates the kinetic energy.
We need to find the kinetic energy of the water.
Let kinetic energy is K.
K = m*g*h
Where g is acceleration due to gravity.
that g= 9.8 m/s^2
now substituting the values in above equation
K= (500) * 10
K= 5000 J
Hence,
he hits the water with kinetic energy of 5000 J.
Learn more about Kinetic energy here:
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Answer:
Force(f)= mass x acceleration
Acceleration (a) is the rate of change in velocity.
F=4N
M=0.2kg
a=F/M
a=4/0.2
a=20m/s^2
Explanation:
Answer:
Explanation:
As we know that thermal expansion coefficient of aluminium is given as
now we also know that after thermal expansion the final length is given as
here we know that
now we will have
The car traverses a distance after time according to
where is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is
5 is pretty close to 4, so we can approximate the square root of 5 by 2. Then the car's velocity after 2 s of travel is given by
which makes C the most likely answer.