Answer:
(0,0) and (7,10)
Step-by-step explanation:
recall that the slope - intercept form of a linear equation can be given as
y = mx + b
where m = slope and b = y intercept
in our case, we are given that slope, m = 10/7, hence our equation becomes
y = (10/7) x + b
since we are not given any information about the y-intercept, we can simply pick a value for b that is most convenient for us.
We pick b = 0, hence the equation simplifies to:
y = (10/7) x ----- eq 1
we can see immediately that if x = 0, y must also = 0
proof if x = 0:
y = (10/7)(0) =0
since 0 is an integer, then (0,0) must be the first point.
we can also observe that for y to be an integer, we must get rid of the denominator 7. We can do this by multiply the right side by 7. Hence we let x = 7:
y = (10/7) x 7
y = 10
hence (7,10) is the second point.
Answer:
a) 
b) 
And replacing we got:
c) 
And adding we got:
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Assuming the following questions:
a. exactly five
For this case we can use the probability mass function and we got:
b. at least one
For this case we want this probability:
And we can use the complement rule and we got:
And replacing we got:
c. between four and six, inclusive.
For this case we want this probability:
And adding we got:
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
x=2.5 or x=-4
Step-by-step explanation:
factorisation= factors:1, 2, 4, 5, 10, 20 (only the positive factors)
We will use the factors 4 and 5.
=(2x-5)(x+4)=0
2x-5=0 || x+4=0
2x=+5 || x=-4
x=2.5 or x=-4
