A chair of weight 90.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F =
38.0 N directed at an angle of 42.0 degrees below the horizontal and the chair slides along the floor.
Using newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.
Using newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.
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Answer:
(a) A =
(b)
(c)
(d)
Solution:
As per the question:
Radius of atom, r = 1.95
Now,
(a) For a simple cubic lattice, lattice constant A:
A = 2r
A =
(b) For body centered cubic lattice:
(c) For face centered cubic lattice:
(d) For diamond lattice: