Answer:
a) 26
b) 26/3
Step-by-step explanation:
a)
1) First, you have to turn 4 1/3 into an improper fraction, so you get 13/3
2) Then you do 13/3 *6/1 =78/3 (so you multiply both numerators and denominators)
3) Lastly, 78/3 can be simplified as 26
b)
1) First you turn both fractions into improper fractions, so you get 13/5 and 10/3
2) Then you do 13/5*10/3 (so you multiply both numerators and denominators)
3) You get 130/15, which can be simplified as 26/3
Answer:
A. 1
B. -1
C. 5
Step-by-step explanation:
A. Using the Formula, we get u sub 2 = 9-9+1, which is just 1
B. Using the Formula, we get u sub 3 = 1-3+1, which is equal to -1
C. Using the Formula, we get u sub 4 = 1-(-3)+1, which is just 1+3+1 = 5
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
10.85
Step-by-step explanation:
hope its right :)
Consider the offered option:
if suppose, that unknown side is '?', then
2*(3x-3)+2*'?'=10x+6;
6x-6+2*'?'=10x+6;
2*'?'=4x+12;
'?'=2x+6
Answer: 2x+6
