A reaction that produces 14.2 grams of a product and the theoretical yield of that product is 17.1 grams is true for the following statements :
The percent yield of the product is 83.0%
The actual yield of the product is 14.2 grams.
<h3>Percentage Yield:</h3>
Percent yield is the percent ratio of actual yield to the theoretical yield.
Mathematically,
percent yield = actual yield / theoretical yield x 100%
actual yield = 14.2 grams
theoretical yield = 17.1 grams
percentage yield = 14.2 / 17.1 × 100%
percentage yield = 83.0409356725 %
percentage yield = 83.0 %
Therefore,
The percent yield of the product is 83.0%
The actual yield of the product is 14.2 grams.
learn more on percentage yield here; brainly.com/question/4180677
Answer:
Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
M_r: 32 60
CH₃OH + CO ⟶ CH₃COOH
m/g: 160
(a) Moles of CH₃OH
(b) Moles of CH₃COOH
(c) Mass of CH₃COOH
A because of the way it looks and how it works
Answer:
The heat would flow from the hot solid to the cool solid until all temperatures are near equal.
Answer:
(3R,4R)-4-bromohexan-3-ol
Explanation:
In this case, we have reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.
Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)
I hope it helps!