The line segment with endpoints (−20, 21) and (0, 0) is graphed on the standard coordinate plane and makes an angle, Θ, with res
pect to the x axis. What is cos Θ?
1 answer:
We have that
<span> points (−20, 21) and (0, 0)
Let
A----> </span>(−20, 21)
B-----> (0, 0)
using a graph tool
see the attached figure
step 1
find the distance AB
<span>applying the Pythagorean theorem
</span>
AB²=20²+21²--------> 841---------> AB=√841-------> 29
AB=29 units
cos <span>Θ=20/29-------> 0.6897
</span>
the angle <span>Θ belong to the second quadrant
therefore
the cos</span><span>Θ is negative
the answer is
the cos </span>Θ is -0.6897
<span> points (−20, 21) and (0, 0)
Let
A----> </span>(−20, 21)
B-----> (0, 0)
using a graph tool
see the attached figure
step 1
find the distance AB
<span>applying the Pythagorean theorem
</span>
AB²=20²+21²--------> 841---------> AB=√841-------> 29
AB=29 units
cos <span>Θ=20/29-------> 0.6897
</span>
the angle <span>Θ belong to the second quadrant
therefore
the cos</span><span>Θ is negative
the answer is
the cos </span>Θ is -0.6897
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<h3>What is a polygon?</h3>A polygon is a two-dimensional closed object with n number of straight sides that is flat or planar and the value of n is always greater than 2 (n>2).
<h3>What is an octagon?</h3>An octagon is a polygon that has 8 number of sides.
As we know that a stop sign has 8 sides, therefore, the polygon that is in the shape of the stop sign is an octagon.
An octagon has 8 sides, and as it is mentioned in the problem that sides and angles appear to be congruent, therefore, the polygon must be a regular polygon.
Hence, the polygon that best describes a stop sign is a regular octagon.
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