Cut 5 equal sections from a 2 foot long ribbond
Part A: 16x=M
Part B: 16x+TY=M
Part C: 16x=580
/16 /16
x=36.25
Mary worked 36 hours and 25 minutes
Answer: c<2
Step-by-step explanation:
-6c<-12
c<-12/-6
c<2
Answer: Alvin = 42 yrs , Elga = 21 yrs
Step-by-step explanation:
Let Elga's age be x , and Alvin's age be y ,since Alvin is two times Elga's age , then
Alvin's age = 2x , that is
y = 2x ............... equation 1
The sum of their ages is 63 implies
x + y = 63 .............. equation 2
Solving the resulting linear equations by substitution method.
Substitute equation 1 into equation 2 , we have
x + 2x = 63
3x = 63
x = 63/3
x = 21
Therefore : Elga is 21 years old , then Alvin will be 21 x 2, which will be 42
Answer:
y = 23
x ≈ 13
Step-by-step explanation:
3y + (y+88) = 180
Solve for y
y =23
6x + 35 = y + 88
substitute y = 23
6x + 35 = 23 + 88
Solve for x
x ≈ 13
