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2 years ago

Please help with numbers7-16. Thank you!

Mathematics

1 answer:

guajiro [1.7K]2 years ago

4 0

First for 7 we need to find out how many ninths are in a third and there are 3/9 in a third so now we multiply 3/9 by 2 which is 6/9 now we subtract 7/9-6/9 which is 1/9 so 1/9 is left. (Iff I'm wrong sorry I did this is like a minute.)

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State the necessary value of nn that will make each statement true.<br> 0.0004 × 0.002 = 8 × 10^n

vodka [1.7K]

Answer:

$-7 = n$

Step-by-step explanation:

$0,002 \times 0,0004 = 0,0000008$

$0,0000008 = 8 \times {10}^{-7}$

* You must make sure that you have seven zeros in your decimal.

I am joyous to assist you anytime.

6 0

2 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

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1 year ago

the areas of the world's oceans are listed in the table order the oceans according to their area from least to greatest.

agasfer [191]

Pacific ocean is the biggest ocean
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2 years ago

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Brut [27]

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Answer:

Step-by-step explanation:

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