That is not right. Is that all your work on the bottom?
Answer:
6546 students would need to be sampled.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of .
The margin of error is:
The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.
This means that
90% confidence level
So , z is the value of Z that has a p-value of , so .
If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?
n students would need to be sampled, and n is found when M = 0.01. So
Rounding up:
6546 students would need to be sampled.
Answer:
The answer is x = -3.
Step-by-step explanation:
Hi there
The parent function is the following:
We need to translate the function 8 units left to get the function:
Therefore the answer is: 8 units left.
Answer:
57/6 60/6 22/6 26/6
Step-by-step explanation:
So the answers for the blanks are 57, 60, 22, 26.
Let me know if I am incorrect.