Answer:// Solve equation [1] for the variable y
[1] y = 2x - 3
// Plug this in for variable y in equation [2]
[2] -2•(2x-3) + 2x = 2
[2] - 2x = -4
// Solve equation [2] for the variable x
[2] 2x = 4
[2] x = 2
// By now we know this much :// Solve equation [1] for the variable y
[1] y = 2x - 3
// Plug this in for variable y in equation [2]
[2] -2•(2x-3) + 2x = 2
[2] - 2x = -4
// Solve equation [2] for the variable x
[2] 2x = 4
[2] x = 2
// By now we know this much :
y = 2x-3
x = 2
// Use the x value to solve for y
y = 2(2)-3 = 1
y = 2x-3
x = 2
// Use the x value to solve for y
y = 2(2)-3 = 1
Step-by-step explanation:
4 squares idk I'm just guessing
Answer:
21n² - 28n + 7
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, that is
3n(7n - 7) - 1(7n - 7) ← distribute both parenthesis
= 21n² - 21n - 7n + 7 ← collect like terms
= 21n² - 28n + 7
You have to use the formule: y2-y1/x2-x1
-2-(-2)/4-(-3)=0/7
Just took the test. A is the right answer.