Solve for y 3y+12=-6

Mathematics

1 answer:

Vadim26 [7]2 years ago

3 0

Answer:

y=-6

Make sure to tell me if im right

Step-by-step explanation:

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What is equivalent to the equation to 1/4 (8 + 6z + 12) ?

Fed [463]

1/4 (8 + 6z + 12)

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Combine like terms :
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1/4 (6z + 20)

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Apply distributive property :
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1/4(6z) + 1/4(20)
3/2z + 5

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Answer: 3/2z + 5
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7 0

2 years ago

Help me plz ill mark u brailiest

antiseptic1488 [7]

Answer:

The product of 21 and 18

Step-by-step explanation:

When you multiply the word is product

The product of 21 and 18

6 0

2 years ago

Read 2 more answers

Q1.Simplify:

solniwko [45]

$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$