This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0 We will replace expression ( 2 on x) with variable t => 2 on x=t =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 => t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 => 2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution.
Check 2: 2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 =>
1-5+4=0 => 0=0 Identity provin solution.
Side of the playground would be : a²+a² = 16²
2a² = 256
a² = 128
a = √128
a = 11.31 m
Simplify brackets
351 = y * 8 + 7
Regroup terms
351 = 8y + 7
Subtract 7 from both sides
351 - 7 = 8y
Simplify 351 - 7 to 344
344 = 8y
Divide both sides by 8
344/8 = y
Simplify 344/8 to 43
43 = y
Switch sides
<u>y = 43</u>
Your Y-intercept is 3.
And your Slope is y = 5x + 3.
It would be a³ b ^4.
Hope This Helps You!
Good Luck Studying :)