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2 years ago

Write a linear equation in slope intercept form that passes through the points (-5, -8)

Mathematics

1 answer:

damaskus [11]2 years ago

7 0

Answer:

y=4/5x-4

Step-by-step explanation:

Use point-slope formula then turn to slope intercept form

y-y₁=m(x-x₁) → y = mx + b

y--8=4/5(x--5)

y+8=4/5x+4

-8 -8

y=4/5x-4

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Work is provided in the image attached.

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nalin [4]

Answer: See below

Step-by-step explanation:

4 parts of the whole are shaded, and there are a total of 10 parts

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1 year ago

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Brand X sells 21 oz. Bags of mixed nuts that contain 29% peanuts. To make their product they combine brand A mixed nuts which co

masha68 [24]

Answer:

Brand X has to mix 8.4 oz of brand A mixed nuts which contain 35% peanuts and 12.6 oz of brand B mixed nuts which contain 25%, to obtain 21 oz. Bags of mixed nuts that contain 29% peanuts.

Step-by-step explanation:

We define

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$B_{B}=1oz @ 25\%$ , wich means Brand b has 1 oz containing 25% peanuts.

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2 years ago

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Sladkaya [172]

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2 years ago

wind resistance varies jointly as an objects surface area and velocity. if an object traveling at 55 miles per hour with a surfa

nikdorinn [45]

Answer:

25 miles per hour

Step-by-step explanation:

Given

$W = Wind\ resistance$

$A = Surface\ Area$

$V = Velocity$

The joint variation can be represented as:

$W\ \alpha\ A*V$

Where:

$V = 55; A = 20; W = 220$

Required

Find V, when: $A = 55; W = 275$

We have:

$W\ \alpha\ A*V$

Express as an equation

$W= k *A*V$

Where k is the constant of variation

Make k the subject

$k = \frac{W}{A*V}$

When: $V = 55; A = 20; W = 220$

We have:

$k = \frac{220}{20 *55 }$

$k = \frac{220}{1100}$

$k = 0.2$

When: $A = 55; W = 275$

We have:

$k = \frac{W}{A*V}$

Substitute: $A = 55; W = 275$ and $k = 0.2$

$0.2 = \frac{275}{55 * V}$

Make V the subject

$V= \frac{275}{55 * 0.2}$

$V= \frac{275}{11}$

$V= 25$

3 0

2 years ago