As this rectangle has it's sides parallel to x axis and y axis
it is easy to find the length of it's sides by counting the number of blocks on each sides.
Let us first find co ordinates of all four points
we would calculate them left and right and up down direction from the origian ( the cross point of x and y axis )
A : it is 2 unit left 2 unit up ( -2 , +2 )
B is 5 unit right 2 unit up ( +5 ,+2)
C is 5 unit right 2 unit down ( +5,-2)
D is 2 unit left 2 unit down ( -2,-2)
Let us now find the distance AB : A is 2 unit left B is 5 unit right so length AB= 2+5 = 7
Let us now find distance AD : A is 2 unit up and D is 2 unit down
so length AD= 2+2= 4
Answer should be 7 x 4 units
Im not good at this, thought Ive done Geometry, But for the first one (180-70) which should be 110, and for the second one I would say 55.
Answer:
The y-intercept is 4.4
Step-by-step explanation:
See picture below.
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
