Answer:
C
Step-by-step explanation:
Its C
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0)
To find the slope, you can use the slope formula and plug in the two points:
(3,63) = (x₁ , y₁)
(5,107) = (x₂, y₂)
m = 22
Now that you know m = 22, plug it into the equation:
y = mx + b
y = 22x + b
To find "b", plug in one of the points into the equation (I will do both points)
(3,63)
y = 22x + b
63 = 22(3) + b
63 = 66 + b Subtract 66 on both sides
-3 = b
(5,107)
y = 22x + b
107 = 22(5) + b
107 = 110 + b Subtract 110 on both sides
-3 = b
y = 22x - 3
Answer:
21% probability you will hit a green light on monday and a red light on tuesday
Step-by-step explanation:
When two events, A and B, are independent, we have that:
In this problem, we have that:
Event A: Green light on monday.
Event B: Red light on tuesday.
The probability that we encounter a green light at the corner of college and main is 0.35
This means that
The probability that we encounter a red light is 0.61:
This means that
These events are independent, that is, the light color on Tuesday is independent of the color on Monday. So
21% probability you will hit a green light on monday and a red light on tuesday
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Find 1/9 :
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Find 9/9 :
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Answer: The total amount is $324.-----------------------------------------------
Answer:
Correct option: (a) 0.1452
Step-by-step explanation:
The new test designed for detecting TB is being analysed.
Denote the events as follows:
<em>D</em> = a person has the disease
<em>X</em> = the test is positive.
The information provided is:
Compute the probability that a person does not have the disease as follows:
The probability of a person not having the disease is 0.12.
Compute the probability that a randomly selected person is tested negative but does have the disease as follows:
Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:
Compute the probability that a randomly selected person is tested negative as follows:
Thus, the probability of the test indicating that the person does not have the disease is 0.1452.