9514 1404 393
Answer:
a (3,-1)
Step-by-step explanation:
The number that "completes the square" is the square of half the x-coefficient, (-6/2)^2 = 9. Rearranging the given function to include the square trinomial, we have ...
f(x) = x^2 -6x +9 -1 . . . . . . . here, we have 8 = 9 - 1
f(x) = (x -3)^2 -1 . . . . . . . . . . vertex form
Comparing this to the generic vertex form ...
f(x) = (x -h)^2 +k . . . . . . . vertex at (h, k)
we see that h=3 and k=-1.
The vertex is (h, k) = (3, -1).
Answer: -3, -4, -5 are the integers
Step-by-step explanation: I don't get what you mean in this problem. You said the sum was -12 but then you are asking for the sum again? Do you want the integers? If so they are -3 -4 and -5 and if you want the sum then it is -12
I hope this helps and brainliest would be appreciated
Answer:
391
Step-by-step explanation:
First you must make the fraction a decimal so you can use it in an equation.
To do so move the . over to the left twice.
.68
Now multiply 575 by .68
575 x .68=391
Answer:
6^-1
Step-by-step explanation:
6^-6 - (-5) = 6^(-6 + 5) = 6^(-1)
A lot of things are going on in this question. Notice how the 5 is handled. It starts off in the denominator as - 5 and when brought to the numerator it becomes -(-5) which makes it + 5.
The answer is then easy. It is 6^(-6 + 5) = 6^-1
You could give the answer as 1/6 but that is not what the question says.
Answer:
Its a i just took the test
Step-by-step explanation:
