Answer:
18 g is the mass produced by 4 g of H₂ and 16 g of O₂
Explanation:
The reaction is:
2H₂ + O₂ → 2H₂O
So, let's find out the limiting reactant as we have both data from the reactants.
Mass / Molar mass = moles
4 g/ 2g/m = 2 moles H₂
16g / 32 g/m = 0.5 moles O₂
2 moles of hydrogen react with 1 mol of oxygen, but I have 0.5, so the O₂ is the limiting.
1 mol of O₂ produces 2 mol of water.
0.5 mol of O₂ produce (0.5 .2)/1 = 1 mol of water.
1 mol of water weighs 18 grams.
Answer:
Exothermic
Explanation:
The energy is the ability to perform a job or to produce heat, and chemical reactions involve a rearrangement of atoms between substances with rupture or formation of chemical bonds.
Endothermic reactions are those that absorb energy in the form of heat.
On the other hand, an exothermic reaction is a way in which energy is released from the system into the environment.
Enthalpy (ΔH) represents the exchange of energy between a thermodynamic system and its surroundings. An endothermic reaction will always have a enthalpy variation (ΔH) greater than zero (ΔH> 0). An exothermic reaction will always have a enthalpy variation (ΔH) less than zero (ΔH< 0).
So in this case, the reaction is exothermic.
Answer:
1.03
Explanation:
You would take 0.00103 and move the decimal like this; 0001.03, we wouldn't have the zeroes in front of the one, as it can throw us off. Therefore, your answer would be 1.03.
Hope I helped! Don't hesitate to let me know if I made a mistake.
Given which are missing in your question:
the flask is filled with 1.45 g of argon at 25 C°
So according to this formula (Partial pressure):
PV= nRT
first, we need n, and we can get by substitution by:
n = 1.45/mass weight of argon
= 1.45 / 39.948 = 0.0363 mol of Ar
we have R constant = 0.0821
and T in kelvin = 25 + 273 = 298
and V = 1 L
∴ P * 1 = 0.0363* 0.0821 * 298 = 0.888 atm