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2 years ago

What activity is accomplished using the genetic code?

1 answer:

5 0

(A) Cells make proteins
Proteins are composed of amino acids. Proteins are made in a process called translation, in which the cell commands.
(B) RNA molecules copied before mitosis begins
DNA molecules are copied before mitosis, not RNA.
(C) mRNA molecules are transcribed to form tRNA
DNA is used as template to form both mRNA and tRNA in a process called transcription.
(D) polypeptides are made into mRNA
mRNA is the template used to make polypeptides in a process called translation.

Therefore, A is the right answer.

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Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0

2 years ago

What does alkalinity mean?

sleet_krkn [62]

Alkalinity is the name given to the quantitative capacity of an aqueous solution to neutralize an acid

8 0

2 years ago

Which is a kingdom? A.Eukarya B. Mammalia C. Prokarya D. Animalia

Art [367]

Hello
D. Animal is is the answer.
Hope this helps u!

Let me know if it's correct.

6 0

2 years ago

How do plants use carbon dioxide

svetoff [14.1K]

Explanation:

Plants use photosynthesis to capture carbon dioxide and then release half of it into the atmosphere through respiration. Plants also release oxygen into the atmosphere through photosynthesis.

if my answer helps you than mark me as brainliest

6 0

2 years ago

Read 2 more answers

Which one of the following molecules can MOST easily pass through the plasma membrane unassisted?

Anton [14]

The molecule that can MOST easily pass through the plasma membrane without assistance is carbon dioxide (CO2). Diffusion is a type of passive transport that occurs when molecules move in favor of a concentration gradient.

During diffusion, molecules move high concentration to a region of low concentration.

Oxygen (O2) and carbon dioxide (CO2) are non-polar gasses that move across cell membranes by a process called simple diffusion.

Simple diffusion is a type of passive transport that does not require energy to move substances across cell membranes.

Learn more in:

brainly.com/question/1619908?referrer=searchResults

4 0

1 year ago