Hi there!
On a level road:
∑F = Ff (Force due to friction)
The net force is the centripetal force, so:
mv²/r = Ff
Rewrite the force due to friction:
mv²/r = μmg
Cancel out the mass:
v²/r = μg
Solve for v:
v = √rμg
v = √(25)(9.81)(0.8) = 14.01 m/s
I think it's C, longer wave length.
Answer:
<em>The amount of electric charge transported = 0.192 C</em>
Explanation:
Electric Charge: This is defined as the product of electric current and time in an electric circuit, The S.I unit of electric charge is Coulombs (C)
Q = It..................... Equation 1
Where Q = Electric charge, I = electric current, t = time.
<em>Given:</em> I = 285 mA, t = 674 milliseconds.
<em>Conversion: (i) Convert from 285 mA to A = (285/1000) A = 0.285 A</em>
<em> (ii) convert from 674 milliseconds to seconds = (674/1000) s = 0.674 s </em>
Substituting these values into equation 1
Q = 0.285 × 0.674
<em>Q = 0.192 C</em>
<em>Therefore the amount of electric charge transported = 0.192 C</em>
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Acceleration = ▵v/▵t
Time = d/v
Fisrt calculate time : ( 118/29 ) = 4 seconds
Then calculate acceleration
A = 29/4 = 7.25 m/s²
Now the force.
Force = mass * acceleration.
F= 1,019 * 7.25
F= 7,387 N
Answer:
The speed stays constant after the force stops pushing.
Explanation:
Speed always stays constant when the force stops pushing it.