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2 years ago

How to solve the formula for Vf in the formula of acceleration?

Mathematics

1 answer:

balandron [24]2 years ago

3 0

A = (Vf - Vi)/t
Multiply by t on both sides to clear the denominator
at = Vf - Vi
Add Vi to both sides.
at +Vi = Vf

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Find the volume and surface area of the square pyramid

Montano1993 [528]

The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.

The complete question is attached below.

<h3>What is the volume and surface area of the pyramid? </h3>

Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.

Then the volume of the pyramid will be

V = (L × B × H) / 3

The surface area of the pyramid will be

SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)

Then the volume will be

V = (7 × 7 × 8) / 3

V = 392/3 cubic units

Then the surface area will be

SA = 2(1/2 × 7 × 10) + 2(1/2 × 7 × 10) + (7 × 7)

SA = 189 square units

Then the correct option is A.

More about the volume and surface area of the pyramid link is given below.

brainly.com/question/23302816

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1 year ago

PLZ HURRY!!!! 15 POINTS!

Daniel [21]

I think it’s 7.5 minutes

5 0

2 years ago

Read 2 more answers

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

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2 years ago

Kendra rides her bike to school each day. It takes her 10 minutes to ride 30 blocks. What unit rate expresses the speed of Kendr

Mashcka [7]

The answer would be 3 blocks per minute

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2 years ago