Answer:
15.02 m/s.
Explanation:
Given that the height of the hill, h= 11.5 m.
Combined mass, m= 54.8 kg
The initial velocity of the combined mass, u=0
Acceleration due to gravity, .
Angle of the path the horizontal, degree.
Let A be the initial position and B be the final position of the sled as shown in the figure.
The path is frictionless so the drag force =0
The gravitational force acting on the combined mass in the downward direction,
The component of force acting in the direction of motion =
Let be the acceleration of the combined mass, m, So,
[ from equation (i)]
Let v be the final velocity of the combined mass.
Now, by using the equation of motion,
Here, s is the displacement in the direction of motion,
So, s= AB
Now, in the right-angled triangle ABO,
Now, from equations (ii), (iii) and (iv), we have
By using the given values, we have
Hence, the speed of the combined mass at the bottom = 15.02 m/s.