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2 years ago

Evaluate x/4+3y^2 for x =8 and y = 3.

Mathematics

1 answer:

Aloiza [94]2 years ago

5 0

Step-by-step explanation:

x/4+3y^2

=8÷4 + 3×3^2

=2+9^2

=2+81

=83

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1/4 + 1/2 + x = −3/4

Ostrovityanka [42]

1/4 + 1/2 + x = −3/4

get a common denominator 1/4

1/4 +2/4 +x = -3/4

combine like terms

3/4 +x =-3/4

subtract 3/4 from each side

x = -3/4 -3/4

x = -6/4

divide top and bottom by 2

x = -3/2

x = -1 1/2

Answer : x = -1 1/2

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2 years ago

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At a local high school, the probability that a student has a job and a car is 0.18. Jackson wants to find the probability that a

makvit [3.9K]

<span>D. the probability that a student has a car or job

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3 years ago

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54044.55 divided by 100

kaheart [24]

54044.55 ÷ 100 = 540.4455

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2 years ago

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At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

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2 years ago

Question 18 (1 point)

neonofarm [45]

Answer:

nsnsjksowwwwwwwwwnwbanansnsn

Step-by-step explanation:

67118/5261717=722282.622

7 0

2 years ago