In neutralization reactions, a base and an acid react to form an ionic salt and water. There is a rule that when a strong base and a strong acid react, the pH of their salt is always neutral which is at pH 7. However, this is only true if equal amounts of acid and base are consumed and that there is no excess. Otherwise, the excess acidity or basicity will adjust the total pH.
Strong acids are the following: HCl, HBr, HI, HClO4, HClO3, HNO3 and H2SO4. Strong bases are KOH, LiOH, NaOH, Ca(OH)2, Sr(OH)2 and Ba(OH)2. Therefore, we can already establish that both of the reactants are strong. The complete reaction is
HBr + KOH ⇒ KBr + H₂O
So, 1 mole of HBr would require 1 mol of KOH, and vice versa. Let'scompute the amount of the initial reactants:
mol HBr: (0.25 mol/L)*(0.92 L) = 0.23 mol HBr
mol KOH: (0.5 mol/L)*(0.46 L) = 0.23 mol KOH
There are equal amounts of acid and base. Thus, pH of the KBr solution is neutral at pH 7.
Answer:
Aluminum; [Ne]3s²3p¹
Arsenic; [Ar]3d¹⁰4s²4p³
Explanation:
<em>Aluminum</em>
From the periodic table, we have that aluminum, Al, is located in period 3, and group 3A of the periodic table
Therefore, the noble gas that comes before aluminum in the periodic table is neon Ne
The electronic configuration of aluminum is 1s²2s²2p⁶3s²3p¹
The electronic configuration of neon is 1s²2s²2p⁶
Therefore, the electronic configuration of aluminum in noble gas notation (Ne) is therefore;
[Ne]3s²3p¹
<em>Arsenic</em>
Arsenic is located after argon, Ar on the periodic table
The electronic configuration of arsenic is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³
The electronic configuration of argon is 1s²2s²2p⁶3s²3p⁶
The electronic configuration of arsenic in noble gas notation (Ar) is given as follows;
[Ar]3d¹⁰4s²4p³
Answer:
16
Explanation:
Group two elements are alkaline earth metal.
All these have two valance electrons. In order to achieve noble gas configuration it loses its two valance and get complete octet.
Reaction with group 16.
Reaction with oxygen,
They react with oxygen and form oxide.
2Ba + O₂ → 2BaO
2Mg + O₂ → 2MgO
2Ca + O₂ → 2CaO
this oxide form hydroxide when react with water,
BaO + H₂O → Ba(OH)₂
MgO + H₂O → Mg(OH)₂
CaO + H₂O → Ca(OH)₂
With sulfur,
Mg + S → MgS
Ca + S → CaS
Ba + S → BaS
The % V/V concentration of a 180-mL disinfectant solution containing 85 mL of isopropyl alcohol is 47 % V/V.
<h3>What is the % V/V concentration?</h3>
It refers to the milliliters of solute for every 100 milliliters of solution.
We have 180 mL of a disinfectant solution that contains 85 mL of isopropyl alcohol (solute).
The % V/V concentration of this solution is:
% V/V = (mL solute/mL solution) × 100% =
% V/V = (85 mL/180 mL) × 100% = 47% V/V
Learn more about % V/V here: brainly.com/question/17055828
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Answer:
Explanation:
Molarity is found by dividing the moles of solute by liters of solution.
We are given grams of a compound and milliliters of solution, so we must make 2 conversions.
1. Gram to Moles
We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.
- C: 12.011 g/mol
- H: 1.008 g/mol
- O: 15.999 g/mol
Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.
6(12.011)+12(1.008)+6(15.999)=180.156 g/mol
Use this number as a ratio.
Multiply by the given number of grams.
Flip the fraction and divide.
2. Milliliters to Liters
There are 1000 milliliters in 1 liter.
Multiply by 2500 mL.
3. Calculate Molarity
Finally, divide the moles by the liters.
The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.
1 mole per liter is also equal to 1 M.
