Answer:
I think it's D) 3
Step-by-step explanation:
hope I helped
Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=
for x²-4x+16=0
x=
x=
x=
x=
x=
x=
the roots are
x=-4 and 2+2i√3 and 2-2i√3
x+y=17000 (x.7+y.15)/100=2000 (7x+7y)+8y=200000. 8y=200000-17000.7 y=61.5.5.5 17000-y=9375=x x=9375
Answer:
314 ft²
Step-by-step explanation:
Data provided in the question:
Depth (height) of the pool = of its radius
let the radius be 'r' ft
thus,
Depth (height) of the pool, h = ft
Volume of the pool = 1570 ft³
also,
Volume of cylinder = πr²h
thus,
1570 ft³ = πr²h
or
1570 ft³ =
or
3140 = 3.14 × r³ [ π = 3.14 ]
or
r³ = 1000 ft³
or
r = 10 ft
Thus,
Area of the bottom surface = πr²
= 3.14 × 10²
= 314 ft²
59.5 feet
Work:
17/10 = x/35
10x=595
59.5