Left side: 63, 72, 16 right side: 36, 4, 35
∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
Learn more about similar triangles here:
brainly.com/question/25882965
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Your choices are correct.
1. adding -3 to the function shifts its graph downward by 3 units.
2. 7^(2x) = (7^2)^x = 49^x
3. f(0) = -6; g(0) = -3, f(0) = 2×g(0)
Answer:
33 cards
Step-by-step explanation:
3 cards already. 5 in 1 hour = 5 x 6 hours = 30 cards + 3 cards
33 cards