Algebraic expression is the expression which consist the variables, coefficients and the constants. The expression for the condition given in the problem is .
Given information
A cab driver is paid $6 plus $0.45 per mile driven.
Total number of total miles is <em>m.</em>
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Algebraic expression</h3>
Algebraic expression is the expression which consist the variables, coefficients and the constants. The algebraic expression are used to solve the condition based problems by expressing them into the algebraic form.
As the cab driver is paid $6 as the fixed amount of the taxi irrespective to the mile driven. Thus this is independent to the other variables and written as the constant in the expression.
As the total miles driven by the cab driver is<em> m</em>. The cost of the per mile driven the car is $0.45. Thus the expression for this condition can be given as,
Hence, the expression for the condition given in the problem is .
Learn more about the algebraic expression here;
brainly.com/question/953809
Answer:
The carnival is losing (on average) $0.15 on each play
Step-by-step explanation:
To find out how much the carnival wins or looses in each play one subtract the expected value (EV) from each play from the amount charged by the carnival for each play ($0.55). If the expected value is higher than what the carnival charges, the carnival is losing money.
Expected is the sum of the payouts of each bet multiplied by its likelihood:
Since the expected value is higher than $0.55, the carnival is losing money, on average, on each play:
The carnival is losing (on average) $0.15 on each play
You multiply like terms first, which means -2/3x*-x. It becomes 2/3x*3y. The coefficient of x is 2/3. The coefficient of y is 3. You can’t combine them because they are not like terms with the variables.
Answer:
14 pushups per min
70 pushups in 5 min
Step-by-step explanation: