Well if your having trouble you should stay after school and ask for help that's what I would do.
Answer:
7
Step-by-step explanation:
So, we know that this process happened 3 times in total. The original amount of kids we can call x, so the next wave filled in the gaps inbetween, so we call that amount x-1, the next wave would be (x+x-1)-1 or 2x-2, and the last would be 4x-4
adding this all up we get 8x-7=49, so 8x = 56 or x = 7
For finding the values, we look at the x - value given. Then we move to where it is on the graph and find its y value.
In part A, when x = -4, the y value looks to be between -3 and -4. Let's put it in the middle and estimate it at -3.5
In part B, when x = 1, the process is similar. Go to x = 1, then go to the graph, then go to the y value. That looks to be at y = -3.
In part C, when x = 4, there are three values that work. We are actually answering part D at this point because we can tell this graph is NOT a function of x. When you have an x -value that goes into the function, you have to get EXACTLY ONE thing that comes out. I bolded "EXACTLY ONE" because those words make the definition work. Two or more, not a function. One, it's a function. None, and it's not in the domain at all. There are three values of y that work, and they are - from top down, 3.5, 0, -2.5.
We answered Part D when observing part C. It's NOT a function because there is not EXACTLY ONE value of y for an x.
And finally, because it's not a function - finding the domain and range is a waste of time. You can't find the domain of something that's not a function - you need a function to have a domain.
Hope that helps.
Answer:
i dont
Step-by-step explanation:
i just want some points ok am so sorry
<span>y= 2*3-4x;
differentiate with respect to t we get dy = -4xdt; -- eqn 1
given dt = 4 substitute in eqn 1 we get , dy =-4 x( 4) = -16x; --eqn2
given x=1 then sub then the value of x in eqn 2 we get dy = -16(1)=-16
ie Ans dy = -16</span>