All categories

2 years ago

What is the equation of the line that passes through the point (2,−4) and has a slope of 2?

Mathematics

1 answer:

vivado [14]2 years ago

3 0

Answer:

y = 2x - 8

Step-by-step explanation:

Since you have the slope of the line and point that the line passes through, you can use "point-slope form", hence the name.

Point-slope form is: $y-y_1=m(x-x_1)$

Substitute the slope (2) into m, and substitute the x-value of the point into $x_1$ and the the y-value of the point into $y_1$ .

$y-(-4)=2(x-(2))$

Simplify this equation.

$y+4=2(x-2)$

Distribute 2 inside the parentheses.

$y+4=2x-4$

Subtract 4 from both sides.

$y=2x-8$ is the final answer.

You might be interested in

Rewrite this radicand as two factors, one of which is a perfect square.

seropon [69]

Answer:

$2 \sqrt{15}$

Step-by-step explanation:

1) rewrite 60 as it's prime factors.

$\sqrt{2 \times 2 \times 3 \times } 5$

2) group the smae prime factors into pairs.

$\sqrt{(2 \times 2)} \times 3 \times 5$

3) Rewrite each pair in exponent form.

$\sqrt{ {2}^{2} \times 3 \times 5 }$

4) use this role:

$\sqrt{ {x}^{2} } = x$

$2 \sqrt{3 \times 5}$

5) Simplify.

$4 \sqrt{15}$

So, therefor, the answer is option 1.

5 0

2 years ago

Read 2 more answers

Secant jkl and jmn are drawn to circle o from an external point ,j. if jk=8,lk=4 and jm=6 what is the length of jn answer

Archy [21]

See the picture attached to better understand the problem

we know that
If two secant segments are drawn to a circle from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
so
jl*jk=jn*jm------> jn=jl*jk/jm

we have
jk=8,lk=4 and jm=6
jl=8+4----> 12

jn=jl*jk/jm-----> jn=12*8/6----> jn=16

the answer is
jn=16