Temporarily subdivide the given area into two parts: a large rectangle and a parallelogram. Find the areas of these two shapes separately and then combine them for the total area of the figure.
By counting squares on the graph, we see that the longest side of the rectangle is the hypotenuse of a triangle whose legs are 8 and 2. Applying the Pyth. Thm., we find that this length is √(8^2+2^2), or √68. Similarly, we find the the width of this rectangle is √(17). Thus, the area of the rectangle is √(17*68), or 34 square units.
This leaves the area of the parallelogram to be found. The length of one of the longer sides of the parallelogram is 6 and the width of the parallelogram is 1. Thus, the area of the parallelogram is A = 6(1) = 6 square units.
The total area of the given figure is then 34+6, or 40, square units.
General form of the line equation is: y= mx + c
where m is the slope and c is the constant
the slope here is given and equal to 3
so, m= 3
y= 3x +c
to get the constant c, substitute with the point in this equation
y= -2 & x = 1
-2 = 3*1 + c
c = -5
then the equation of the line is y = 3x -5
y = 3x -3 -2
y +2 = 3(x-1)
the answer is (B)
Answer:
D: {9, 21, 33}
Step-by-step explanation:
Ken worked 2, 8 and 14 hours on 3 separate days.
For working 2 hours, his earnings were f(2) = 2(2) + 5, or 9;
For working 8 hours, his earnings were f(28) = 2(8) + 5, or 21; and
For working 14 hours, his earnings were f(14) = 2(14) + 5, or 33
Thus, the range of this function for the days given is {9, 21, 33} (Answer D)
Answer:
Step-by-step explanation:
Simplify:
Group same factor:
Add :
Apply the distributive law: -(a+b) = -a - b
Group same factor:
Subtract:
Add:
Group same factor:
Hence answer =
<u><em>~lenvy~</em></u>
Answer:
y = 3
Step-by-step explanation:
Substitute the given points into the function and solve for a and b
Using (2, 12)
12 = ab² → (1)
Using (5, 96)
96 = a
→ (2)
Divide (2) by (1)
= 
, that is
b³ = 8 ( take the cube root of both sides )
b = ![\sqrt[3]{8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D)
= 2
Substitute b = 2 into (1) and solve for a
12 = a2² = 4a ( divide both sides by 4 )
3 = a
Thus
y = 3 ← is the exponential function
