Answer:
D: 160
Step-by-step explanation:
Fifth graders read 68, which is easy to see. Fourth graders read between 48 and 52, the bar appears to be directly in the middle of the two lines, so we say they read 50. Third graders read between 40 and 44, again the bar appears to be directly in the middle so we say they read 42.
42+50+68=160
Answer:
1. 40 members
2. 4 cheerleaders
3. 40 marbles
4. 2 marbles
5. 8
6. 24
Step-by-step explanation:
1. cross multiply 12/x=30/100
2. cross multiply 12/x=10/100
3. 18/x=45/100
4. x/40=5/100
5. we know 5% is 2 marbles. multiply by 4 to get 8 marbles.
6. 20%=8 marbles. 60/20= 3. 3 x 8= 24 marbles.
AB + CD = BC + DA
<span>Where A, B, C, and D are points on the quad, and AB is the length of the line A to B, etc. </span>
<span>Since you know three sides, you can easily solve for the fourth. </span>
Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
x = −6 would be your answer
:)
