The new oscillation frequency of the pendulum clock is 1.14 rad/s.
The given parameters;
- <em>Mass of the pendulum, = M </em>
- <em>Length of the pendulum, = L</em>
- <em>Initial angular speed, </em><em> = 1 rad/s</em>
The moment of inertia of the rod about the end is given as;
The moment of inertia of the rod between the middle and the end is calculated as;
Apply the principle of conservation of angular momentum as shown below;
Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.
Learn more about moment of inertia of uniform rod here: brainly.com/question/15648129
The total work is
(mass of the elevator, kg) x (9.8 m/s²) x (9.0 m) Joules .
Force of gravity = Mass x Gravitational force
Fg=mg
Fg = (5.7)(9.8)
Fg= 55.86 N