Time 6 years Interest rate 1.9% Principal- $850 What amount of simple interest will be earned? $16.15 O $96.90 $946.90 $9,690.00

Consider the function f(x) = 6sin(x^2) on the interval 0 ≤ x ≤ 3.

Vitek1552 [10]

<span> a) F' = 6 sin(x^2) = 0
x^2 = pi
x = sqrt(pi)

b) Fmax = F(1) + integral [1, pi] f(x) dx = 9.7743 </span>

4 0

2 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Anuta_ua [19.1K]

Answer:

a) c = 1/15

b) =2/5

c) = 3/5

d) No, it cannot be the PMF of y.

Step-by-step explanation:

We have that

$p_X(x)\geq0$

4 0

2 years ago

34xy

mr Goodwill [35]

3/4, x, and y that is the answer

6 0

2 years ago

Read 2 more answers

A coordinate grid showing Number of Classes on the horizontal x-axis and Total Cost in dollars on the vertical y-axis with 2 lin

Oksana_A [137]

The system of equations representing these costs are; y = 7.5x and y = 5.5x + 10

<h3>How to find the equation of a line?</h3>

The slope of the first line is;

m = (y2 - y1)/(x2 - x1)

m = (32 - 10)/(4 - 0)

m = 5.5

Now, the first coordinate has a y-intercept of 10. Thus, the equation here for the cost is; y = mx + c = 5.5x + 10

The slope of the second line is;

m = (y2 - y1)/(x2 - x1)

m = (15 - 0)/(2 - 0)

m = 7.5

Now, the first coordinate has a y-intercept of 0. Thus, the equation here for the cost is; y = mx + c = 7.5x + 0 = 7.5x

Thus, the system of equations representing these costs are;

y = 7.5x and y = 5.5x + 10

Read more about Equation of a line at; brainly.com/question/13763238

#SPJ1

5 0

1 year ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

2 years ago