Answer:
3234.2 W
Explanation:
Since intensity I = Power/Area. The intensity of the light from the sun, I = power radiated by sun/area of sphere of radius, r = 1.5 × 10¹¹ m.
So, I = 3.9 10²⁶W/4π(1.5 × 10¹¹ m)² = 2.069 × 10³ W/m².
Now, the power radiated on the patch of area 0.570 m² at the equator is
P = Icos27/A = 2.069 × 10³ W/m² cos27/0.570 m² = 1843.49/0.570 = 3234.2 W
Answer:
=9.72 m/s
Explanation:
From the Newton's laws of motion;
x=2(v²cos∅sin∅)/g
Using geometry we see that 2 cos∅sin∅ = sin 2∅
Therefore, x= (v²sin 2∅)g, where v is the take off speed x the range and ∅ the launch angle.
Making v the subject of the formula we obtain the following equation.
v=√{xg /(sin 2∅)}
x=7.80
∅=27.0
v=√{7.8×9.8/sin(27×2)}
v=√94.485
v=9.72 m/s
Answer:
First Question
Second Question
The wavelength is for an X-ray
Explanation:
From the question we are told that
The width of the wall is
The first excited state is
The ground state is
Gnerally the energy (in MeV) of the photon emitted when the proton undergoes a transition is mathematically represented as
Here h is the Planck's constant with value
m is the mass of proton with value
So
=>
Generally the energy of the photon emitted is also mathematically represented as
=>
=>
=>
Generally the range of wavelength of X-ray is
So this wavelength is for an X-ray.
Answer:
B) Absorbed energy results in the change in potential energy.
Explanation:
i got it wrong on usatestpreo
Answer:
Explanation:
Conclusion is simple you can just say that it is the value written in words form only.
Nothing else is written about it