A 100 hz sound wave is traveling through the air. if we increase the frequency to 200 hz, this will _____ the wavelength. a 100
1 answer:
The correct answer is "decrease":
<span>A 100 hz sound wave is traveling through the air. if we increase the frequency to 200 hz, this will INCREASE the wavelength.
Let's see why. The basic relationship between frequency and wavelength of a wave is
</span>
<span>where
v is the speed of the wave
f its frequency
</span>
its wavelength
<span>
We can see from this equation that, if the frequency is increased, if the speed of the wave does not change (and this is the case), then the wavelength of the wave must decrease, since the ratio </span>
becomes smaller.
<span>A 100 hz sound wave is traveling through the air. if we increase the frequency to 200 hz, this will INCREASE the wavelength.
Let's see why. The basic relationship between frequency and wavelength of a wave is
</span>
<span>where
v is the speed of the wave
f its frequency
</span>
<span>
We can see from this equation that, if the frequency is increased, if the speed of the wave does not change (and this is the case), then the wavelength of the wave must decrease, since the ratio </span>
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Answer:
1.8 × 10⁻⁸ Hm
Explanation:
Given that:
The refractive index of the film = 19
The wavelength of the light = 136.8 μ m
The thickness can be calculated by using the formula shown below as:
Where, n is the refractive index of the film
is the wavelength
So, thickness is:
Thickness = 1.8 μ m
Since,
1 μ m = 10⁻⁸ Hm
So,
Thickness = 1.8 × 10⁻⁸ Hm
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Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.
We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.
The efficiency of an ideal Carnot heat engine can be written as:
where
is the temperature of the cold region
is the temperature of the hot region
For the engine in our problem, we have
and 
, so the efficiency is
where
For the engine in our problem, we have