Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
Step-by-step explanation:
LHS= sin 3x/sin x - cos 3x/cosx
Taking LCM,
<u>=</u><u>sin3xcosx- cos3xsinx</u>
sinxcosx
<u>=</u><u>sin(3x-x)</u>
sinxcosx
= <u>2sin2x</u>
2sinxcosx
=<u> </u><u>2sin2x</u><u> </u>
sin2x
=2
= RHS.
Proved.
Answer:
155
Step-by-step explanation:
5*5=25
((5*13)/2)*4=130
130+25=155
Yeah post the questions I'll see if I can answer them