The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
<u>Step-by-step explanation:</u>
- There are 1 red ball and 4 white balls in a box.
- The total number of balls in the box = 1 red + 4 white = 5 balls.
The two balls are drawn without replacement.
<u>Drawing the first ball :</u>
The first draw should be a red ball.
The probability to get a red ball = No.of red balls / Total balls in the box.
We know that, No. of red balls is 1 and total balls in the box is 5.
P(red ball) = 1/5
<u>Drawing the second ball :</u>
The second draw should be a white ball.
The probability to get white ball = No.of white balls / Total balls in the box.
We know that,
No. of white balls is 4.
The total balls in the box after the first draw will be 4 balls.
P(white ball) = 4/4
The probability of getting a red ball on the first drawn and a white ball on the second draw = P(red ball) × P(white ball)
⇒ (1/5) × (4/4)
⇒ 4/20
⇒ 1/5
Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
Answer:
56 in
Step-by-step explanation:
Square ....so each side is = x
x * x = area = 196
x^2 = 196
x = sqrt (196) = 14 in
perimeter = x + x + x + x = 56 in
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Answer:
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Step-by-step explanation:
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Answer: Length = 70 feet
Concept:
Here, we need to know how to find the perimeter of a rectangle.
Perimeter (rectangle) = 2 (l + w)
l = length
w = width
Solve:
<u>Given information</u>
l = l
w = 51 feet
P = 242 feet
<u>Given expression</u>
P = 2 (l + w)
<u>Substitute values into the expression</u>
242 = 2 (l + 51)
<u>Divide 2 on both sides</u>
242 / 2 = 2 (l + 51) / 2
121 = l + 51
<u>Subtract 51 on both sides</u>
121 - 51 = l + 51 - 51
Hope this helps!! :)
Please let me know if you have any questions
