Momentum should be conserved. The momentum of both
objects must balance with their initial and final momentum.
Let m1 and v1 be the mass and velocity of the
bowling ball
And m2 and v2 be the mass and velocity of the
bowling pin
(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f
30 kg m/s + (1.5 kg)(0 m/s) = 13kg m/s + 1.5v2f
V2f = 11.33 m/s
<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>
Answer: The bug will remain motionless
Explanation:
According to Newton's first Law of Motion (sometimes called Law of Inertia):
<em>An object at rest or describing a uniform straight line motion (moving at constant velocity), will remain at rest or moving unless an external force is applied to it and changes its state of rest or motion.
</em>
In other words:
An object or body will keep its state of motion until an external force changes its state
This means that objects tend to remain in its state of motion, and is the definition of the inertia, as well.
In addition, according to his law, an object in rest can be in equilibrium (net force equals to zero), and a moving object can also be in equilibrium, as long as it keeps a constant velocity.
<h2>
This is why the bug, which is at rest will remain at rest, although the ants are simultaneously pulling it in different directions, since the resultant of all these forces is zero.</h2>
I think It would be C. Checking a prediction. Sorry if I’m wrong
Answer:
the tension in the string an instant before it broke = 34 N
Explanation:
Given that :
mass of the ball m = 300 g = 0.300 kg
length of the string r = 70 cm = 0.7 m
At highest point, law of conservation of energy can be expressed as :
The tension in the string is:
Thus, the tension in the string an instant before it broke = 34 N
Ohm's Law states V = IR
So,
I = V/R
The answer is B. 10/5=2 amps