If you want 3/4 in 64's, multiply the numerator (3) by 16, as 4 x 16 = 64.
<span>3 x 16 </span>
<span>--------- </span>
<span>4 x 16 </span>
<span>= 48/64</span>
Answer:
f(g(x)) = x^4 + 12x^3 + 14x^2 -132x + 123
Step-by-step explanation:
Here, we simply will place g(x) into f(x)
So every x in f(x) is replaced by g(x)
Thus, we have;
(x^2 + 6x + 11)^2 + 2
= (x^2+6x-11)(x^2 + 6x -11) + 2
= x^4 + 6x^3 -11x^2 + 6x^3 + 36x^2 - 66x -11x^2 -66x + 121 + 2
= x^4 + 12x^3 + 14x^2 -132x + 123
Answer:
B
Step-by-step explanation:
e is the base of the natural log system.
take the natural log of both sides.
ln(e^a) = ln(60) The power can come down
a ln(e) = ln(60) The natural log of e = 1
a * 1 = ln (60)
a = ln(60)
Answer:
<h2>FALSE</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
order of PEMDAS
- parentheses
- exponent
- multiplication or
- division
- addition
- subtraction
<h3>let's solve:</h3><h2><u>L.</u><u>H.S</u><u>=</u></h2>
- <u>
</u> - <u>
</u>
<h2><u>≠R.H.S</u></h2>
therefore
<h3>the equality is false</h3>
Answer:
P value is 0.1932
conclusion is that find value P greater than hypothesis test at the 0.05 level
Step-by-step explanation:
Given data
registered organ donors P = 40%
sample n = 200
registered organ donors x = 74
hypothesis test α = 0.05
to find out
P-value and state a conclusion
solution
we take a trail p less than 40 % i.e 0.40
so p = x/n
p = 74 / 200 = 0.37
so we find here Z value i.e
Z = p - P / √(PQ/n)
here Q = 1-p = 1-0.40 = 0.60
so Z = 0.37 - 0.40 / √(0.40×0.60/200)
Z = - 0.866
so p value for Z (-0.866) from z table
P value is 0.1932
and conclusion is that find value P greater than hypothesis test at the 0.05 level
