<span>No. Its x=4. You couldn't cut the box to much lower without it being absurd.
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Answer:
- ABCD is a rhombus, and a parallelogram
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<h3>Given </h3>
- Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)
First, plot the points (see attached picture).
Then, connect all the points.
<h3>We see that:</h3>
- Opposite sides are parallel,
- Diagonals are perpendicular.
From our observation the figure is rhombus.
Let's confirm it with the following.
1) Find midpoints of diagonals and compare.
- AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
- BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2
The midpoint of both diagonals is same (- 2, 2).
2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.
- m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
- m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3
- m(AC) × m(BD) = 3/4 * (- 4/3) = - 1
<u>Confirmed.</u>
So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.
We will make use of the concept of prime factors for solving this question. The prime factors of 1517 are:
So, as can be clearly seen the Niagara Fall tour operator can either sell 37 tickets for $41 each or 41 tickets for $37 each.
Now, we know that we cannot reach $37 using just three bills. Thus, the only option left to us is $41 which can be broken down into three bills of $20,$20 and $1. This satisfies our condition.
Thus the cost of a ticket was $41 and 37 such tickets were sold.
Answer:
-2 > x < 2
Step-by-step explanation:
Given that:
2x + 6 > 2
Subtracting 6 from both sides:
2x + 6 -6 > 2-6
2x > -4
Dividing by 2 on both sides:
x > -2
For second equation:
5x< 6 + 2x
Subtracting 2x from both sides:
5x - 2x < 6 + 2x -2x
3x < 6
Dividing by 3 on both sides:
x < 2
Result: -2 > x < 2