How do the hazards from a quiet eruption differ from those of an explosive eruption?

1 answer:

4 0

<span>Hazards from huge explosive eruptions comprise extensive ash-falls with small glass particles in it, pyroclastic flows (combinations of hot gases and pumice chunks), and immense lahars which are volcanic mud flows which can even include debris. These put people within the area in danger. Nearby properties get damaged as well within a circumference of tens to hundreds of miles away from the volcano. These eruptions can extensively cause a change to the global climate too. Hazards from quiet eruptions include lava flows which contain exploding fires and creating gas clouds which are rich in chlorine where lava pours into the sea. This can cause damage to wildlife and sea creatures.</span>

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A single replacement reaction is a reaction in which one element replaces a similar element within a compound. True or false?

AleksAgata [21]

Answer:

true

Explanation:

A single replacement reaction is a reaction that an element is displaced with another element in a compound

A+BC------AC+B

Mg+2HCl-------MgCl2+H2

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3 years ago

Which group is composed entirely of nonmetals?

frozen [14]

Group 18 is the only group in periodic table in which all the elements are nonmetals. This group contains F, Cl, Br, I and At and also the other name of this group is halogen which means salt producer.

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1 year ago

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Convert 23.92inHg to Pa.

andriy [413]

Answer:

3189.07Pa

Explanation:

The conversion of 23.92mmH to Pa can be achieved in the following way:

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23.92mmHg = (23.92x101325)/760 = 3189.07Pa

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2 years ago

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What is the name of the gas law relating pressure and volume at a<br> constant temperature?

pochemuha

Answer:

Charles Law

Explanation:

Charles's law (also known as the law of volumes) is an experimental gas law that describes how gases tend to expand when heated. A modern statement of Charles's law is: This relationship of direct proportion can be written as: V∝T

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In a hydrogen atom, the electron and the proton are seperated by about 0.5 angstroms, 5.0×10−11 m. what is the acceleration of a

nadya68 [22]

The charge of proton and electron is equal in magnitude that is $1.6\times 10^{-19} C$ . The distance between electron and proton is $0.5 \AA$ or $5\times 10^{-11} m$ .

Force exerted on electron by proton is calculated as follows:

$F= \left | \frac{kq_{e}q_{p}}{r^{2}} \right |$

Here, k is Coulomb's constant, $q_{p}$ is charge on proton, $q_{e}$ charge on electron and r is distance between them.

Putting the values,

$F= \left | \frac{(8.99\times 10^{9}N m^{2}/C^{2})(1.6\times 10^{-19} C)(1.6\times 10^{-19} C)}{(5\times 10^{-11} m)^{2}} \right |=9.2\times 10^{-8} N$