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2 years ago

A: value of g(2) is larger than value of g(-4)

Mathematics

1 answer:

loris [4]2 years ago

8 0

Answer:

$g(2) = 4(2) - 5 \\ = 8 - 5 \\ = 3 \\ \\ g( - 4) = 4( - 4) - 5 \\ = - 16 - 5 \\ = - 21$

The answer is A

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A circle centered at the origin has a radius of 10 units. The terminal side of an angle, Theta, intercepts the circle in Quadran

Tanzania [10]

Since the circle is centered at the origin, we can use the equations
x² + y² = r²
x = r cos θ
y = r sin θ

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2 years ago

find x. assume that segments that appear tangent are tangent. please help need answer and how to do it.

Pavlova-9 [17]

Triangle ABC is a right triangle, meaning we can use the Pythagorean Theorem to find x.
The formula for the Pythagorean Theorem is:
$a = \sqrt{ {b}^{2} + {c}^{2} }$
where a is the hypotenuse, and b and c are the legs.
In this problem, we have the vertical leg as 16, the horizontal leg as x, and the hypotenuse as 20. Therefore, we can say that
$a = 20 \\ b = 16 \\ c = x$
Therefore, we can plug into the formula to find x: $a = \sqrt{ {b}^{2} + {x}^{2} } \\ {a}^{2} = { \sqrt{ {b}^{2} + {x}^{2} } }^{2} \\ {a}^{2} = {b}^{2} + {x}^{2} \\ {a}^{2} - {b}^{2} = {x}^{2}$
We first change the variable c to x and square both sides of the equation. Then we subtract b^2 from both sides.
${x}^{2} = {a}^{2} - {b}^{2} \\ \sqrt{ {x}^{2} } = \sqrt{ {a}^{2} - {b}^{2} } \\ x = \sqrt{ {a}^{2} - {b}^{2} }$
We square root each side to find the variable answer for x. Then we plug in the numbers: $x = \sqrt{ {(20)}^{2} - {(16)}^{2} } \\ x = \sqrt{400 - 256} \\ x = \sqrt{144} \\ x = 12$
We find that x = 12. The answer is A. 12.

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2 years ago