The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is seconds
So, the time required for 200 wing beat seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Answer:
6
Step-by-step explanation:
Let "a number" = x
44 = 8x - 4
Simplify. Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First add 4 to both sides:
44 (+4) = 8x - 4 (+4)
44 + 4 = 8x
48 = 8x
Isolate the variable, x. Divide 8 from both sides:
(48)/8 = (8x)/8
x = 48/8
x = 6
6 is your answer.
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106 square feet.. your welcome
Answer:
3
Step-by-step explanation:
3x(6+3)=27, shed have 1 inch left over
Answer:
<h3>
A = 0.5(2x+6)(6x+13) = 6x² + 49x + 78</h3>
Step-by-step explanation:
H = 2x+6 - the hight
3H = 3(2x+6) - triple the hight
3H-5 = 3(2x+6) - 5 - five less than triple the height
Area of triangle: A = 0.5BH
B = 3(2x+6)-5 = 6x + 18 - 5 = 6x + 13
H = 2x+6
So:
A = 0.5(2x+6)(6x+13) = (x+6)(6x+13) = 6x² + 13x + 36x + 78
A = 6x² + 49x + 78