What’s the equation of a line that passes through (-9,10) and y=3/2x - 3/2
1 answer:
Answer:
y = 3x/2 + 23 1/2
Or
y = 3x/2 + 47/2
Step-by-step explanation:
Find the slope
y = 3/2x - 3/2
Equation of a line
y = mx + c
m = 3/2
using a point slope form equation
Substitute the point into the equation
( -9 , 10)
y - y1 = m( x - x1)
x1 = -9
y1 = 10
y - 10 = 3/2( x - (-9)
y - 10 = 3/2( x + 9)
Open the bracket
y - 10 = (3x + 27)/2
y = ( 3x + 27)/2 + 10
LCM = 2
y = ( 3x + 27 + 20)/2
y = ( 3x + 47)/2
Separate to get the value of slope and intercept
y = 3x/2 + 47/2
y = 3x/2 + 23 1/2
The equation of the line is
y = 3x/2 + 23 1/2
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