Answer:
The rate of change of the temperature is 0.0365 Kelvin per minute.
Explanation:
<u>Step 1</u>: Given data
ideal gas law: P*V = n*R*T
with P= pressure of the gas ( in atm) = 9.0 atm
with V= volume of the gass (in L) =12L
with n = number of moles = 10 moles
R = gas constant = 0.0821 L*atm* K^−1*mo^−1
T = temperature = TO BE DETERMINED
The volume decreases with a rate of 0.17L/min = dV/dT = -0.17
The pressure increases at a rate of 0.13atm/min = dP/dT
<u>Step 2:</u> The ideal gas law
P * [dV/dT] + V * [dP/dT] = nR * dT/dt
9 atm * (-0.17L/min) + 12L * 0.13atm/min = 10 moles * 0.0821 L*atm* K^−1*mo^−1 *dT/dt
0.03 = 0.821 * dT/dt
dT/dt = 0.03/0.821
dT/dt = 0.0365
Since the gas constant is expressed in Kelvin and not in °C, this means that <u>the rate of chagnge of the temperature is 0.0365 Kelvin per 1 minute.</u>
Answer:
A flame test is an analytical procedure used in chemistry to detect the presence of certain elements, primarily metal ions, based on each element's characteristic emission spectrum. The color of flames in general also depends on temperature; see flame color.
Explanation:
I hope it's help u ;)
Answer:
Answers are in the explanation.
Explanation:
<em>Given concentrations are:</em>
- <em>SO₂ = 0.20M O₂ = 0.60M SO₃ = 0.60M</em>
- <em>SO₂ = 0.14M O₂ = 0.10M SO₃ = 0.40M </em>
- <em>And SO₂ = 0.90M O₂ = 0.50M SO₃ = 0.10M</em>
<em />
In the reaction:
2SO₂(g) + O₂(g) ⇄ 2SO₃(g)
Kc is defined as:
Kc = 15 = [SO₃]² / [O₂] [SO₂]²
<em>Where concentrations of each species are equilbrium concentrations.</em>
<em />
Also, you can define Q (Reaction quotient) as:
Q = [SO₃]² / [O₂] [SO₂]²
<em>Where concentrations of each species are ACTUAL concentrations.</em>
<em />
If Q > Kc, the reaction will shift to the left until Q = Kc;
If Q < Kc, the reaction will shift to the right until Q = Kc
If Q = Kc, there is no net reaction because reaction would be en equilibrium.
Replacing with given concentrations:
- Q = [0.60M]² / [0.60M] [0.20M]² = 15; Q = Kc → No net reaction
- Q = [0.40M]² / [0.10M] [0.14M]² = 82; Q > Kc, → Reaction will shift to the left
- Q = [0.10M]² / [0.50M] [0.90M]² = 0.015; Q < Kc → Reaction will shift to the right
<em />
By use of combined gas law
P2= T2P1V1/V2
v1=5L
P1=540 torr
T1=25+273=298k
V2=15 L
T2=32+273=305 k
P2 is therefore=( 305k x 540 torr x5 L) /( 15L x 298)= 184.23 torr
Answer:
the concentration of bicarbonate is <em>[HCO₃⁻] = 0,03996 M </em>and carbonate is <em>[CO₃²⁻] = 3,56x10⁻⁵ M.</em>
Explanation:
Carbonate-bicarbonate is:
HCO₃⁻ ⇄ CO₃²⁻ + H⁺ With pka = 10,25
Using Henderson-Hasselbalach formula:
pH = pka + log₁₀
7,2 = 10,25 + log₁₀
8,91x10⁻⁴ = <em>(1)</em>
Also:
0,040 M = [CO₃²⁻] + [HCO₃⁻] <em>(2)</em>
Replacing (2) in 1:
<em>[HCO₃⁻] = 0,03996 M</em>
Thus:
<em>[CO₃²⁻] = 3,56x10⁻⁵ M</em>
I hope it helps.