By the Fundamental Theorem of Arithmetic, all number can be expressed as a product of prime numbers.
So naturally, lets divide 120 by an easy prime number.
We know that 120 is even, so lets try 2
120/2 = 60
lets keep dividing it by two until it becomes odd or prime
60/2 = 30
30/2 = 15
now lets see, what are some factors of 15?
Well the obvious ones are 3 and 5, both of which are prime. So now we can just count up how many times we divided it by 2
120/2 = 60
60/2 = 30
30/2 = 15
and 15 is just 3 x 5, so:
<span>
120=(<span>23</span>)×(3)×(5)</span>
or
<span><span>
120 = 2 × 2 × 2 × 3 × 5</span></span>
8792 mi long because 56 * 157 = 8792
Answer:
The answer should be C
Step-by-step explanation
I've had this problem before, and know it should most definitely be C.
Hope I helped!
Answer:
i love brent faiyaz
Step-by-step explanation:
there you are
Answer:
-5.7
Step-by-step explanation:
OUR EQUATION IS A QUADRATIC EQUATION
Let Δ be our dicriminant :
- a= 1
- b= 5
- c= -4
- Δ= 5²-4*1*(-4) =25 +16 =41≥0
- so we have two solutions x and y
- x= (-5-√41)/2 = -5.7
