All categories

2 years ago

Between what two integers is 130? 10 and 11 11 and 12 12 and 13 13 and 14

Mathematics

1 answer:

Nostrana [21]2 years ago

4 0

Answer:

13 and 14

Step-by-step explanation:

You might be interested in

Melinda spend $14.25 on school supplies Dr spend $2.30 more than Melinda

zloy xaker [14]

14.25+2.30=16.55 so, dr spent $16.55 on school supplies

3 0

2 years ago

Read 2 more answers

What is 19/5 as mixed number

icang [17]

3 4/5 because if 5 only goes into 19 3 times and then there is 4/5 left

6 0

2 years ago

Read 2 more answers

How do you divide 85 and 5?

AVprozaik [17]

Division is like sharing so 85 things that are shared between 5 people
85÷5=17 that is how much each person gets
so 17 is your answer

5 0

2 years ago

Read 2 more answers

Cafeteria use 637.2 kg of beans to make nine batches of chili what quantity of beans went into each one

SOVA2 [1]

Answer:

70.8 kg

Step-by-step explanation:

This is a division problem.

637.2 kg / 9 = 70.8

Answer: 70.8 kg

6 0

2 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

2 years ago