Answer:
the points where the ellipse crosses the x- axis are (1.73, 0) and (-1.73, 0)
Step-by-step explanation:
To find the points at which a graphic crosses the x-axis we need to find the values for x where y = 0.
Therefore, in the equation x²- xy + y² = 3 we are going to make y = 0 and solve for x
x² - xy + y² = 3
x²- x(0) + (0)² = 3
x² = 3
x = ±√3
x₁ = 1.73 and x₂ = -1.73
Therefore, the points where the ellipse crosses the x- axis are (1.73, 0) and (-1.73, 0)
I think it would be like how many times does 5 go into 48.. and that would be 9 and 3/5
The sum of the angles of a quadrilateral is 360 degrees. So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.
The four triangles, AQB, BRC, CSD, and DPA are all isosceles. So angle QBA = angle BAQ, etc. We find QBA = (180-24)/2 or 78 degrees.
RBC = (180-114)/2 = 33 degrees.
180 - (78 + 33) is the measure of angle B: 69 degrees.
The student should be able to see how to calculate the missing information from this.
Answers: choice C and choice E
Plugging x = 3 and y = -1 into both equations of choice C lead to a true result (the same number on both sides). This is why the system of equations listed in choice C is one possible answer. Choice E is a similar story.
If your teacher didn't mean to make this a "select all that apply" type of problem, then it's likely your teacher may have made a typo.