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<em>We will assume the tent is in the shape of a triangular prism.</em>
The volume of a triangular prism can be found with the following formula, where is the width at the base, is the height, and is the length.
Substitute in the known values.
Simplify — use multiplication.
Simplify — use division.
The volume — or in this case, the amount of living space — is .
Answer:
m∠X = 29°
m∠V = 61°
m∠W == 90°⇒given
Step-by-step explanation:
∵ ΔXWV is right angle at W
∴ m∠W = 90°
∴ m∠X + m∠V = 180° - 90° = 90°
∵ m∠X = 2x + 5 and m∠V = 4x +13
∴ 2x + 5 +4x + 13 = 90
∴ 6x + 18 = 90
∴ 6x = 90 - 18 =72
∴ x = 72/6 = 12
∴ m∠X = 2(12) + 5 = 29°
∴ m∠V = 4(12) + 13 = 61°
Most of the information's required for solving the question is already given in the question.
Height of the building that casts a shadow of 20 m = 32 m
Then
Height of the man that casts a shadow of 1.2 m = (32/20) * 1.2 meter
= 3.2 * 1.2 meter
= 3.84 meter
So the actual height of the person casting a shadow of 1.2 meter is 3.84 meters. I hope that the procedure used for solving the problem is easy enough for you to understand. You can definitely use this method in future for solving problems of similar type without requiring any additional help from outside.
Answer:
D
Step-by-step explanation:
ince the only colors are white, green, yellow, red, and purple, we can see that NOT getting red or purple is the same as GETTING white, green or yellow
So, P(NOT getting red or purple) = P(GETTING white, green or yellow)
There are 60 jellybeans in total.
Number of jellybeans that are white, green or yellow = 22 + 18 + 11 = 51
So, P(GETTING white, green or yellow) = 51/60
= 17/20
= 0.85
Answer: D
Answer:
3yz² - 3z² - 5y + 7
Step-by-step explanation:
Sum of two polynomials = –yz² - 3z² – 4y + 4
One of the polynomial = y - 4yz²- 3
Find the other polynomial
The other polynomial = sum of the polynomials - one of the polynomial
= –yz² - 3z² – 4y + 4 - (y - 4yz² - 3)
= –yz² - 3z² – 4y + 4 - y + 4yz² + 3
= -yz² + 4yz² - 3z² - 4y - y + 4 + 3
= 3yz² - 3z² - 5y + 7
A. 0 -2yz?
B. – 4y + 7 01 - 2yz
C. – 3y + 1 0 -5yz² + 3z² – 3y + 1 D. 3yz² - 3z² – 5y + 7