7+z / 2
z = 10
replace the value of z
7 +10 /2
use order of operations ( division comes before addition)
7+5 = 12
<span>Square root of y^2 = y
so
</span><span>Square root of y^2 times y^2 = y * y^2 = y^3
answer
y^3</span>
Answer: 20
H(c) = 6.4 + 0.6c
<u>6.4</u> is the constant.
When the height of the cups is <u>18.4</u> the function is:
18.4 = 6.4 + 0.6c
Then, you add <u>6.4</u> from both sides
18.4 - 6.4 + 6.4 = 6.4 + 0.6c - 6.4 + 6.4
Simplify
18.4 = 6.4 + 0.6c
Switch sides
6.4 + 0.6c = 18.4
Multiply both sides by <u>10</u>
6.4 x 10 + 0.6c x 10 = 18.4 x 10
Refine
64 + 6c = 184
Subtract <u>64</u> from both sides
64 + 6c - 64 = 184 - 64
Simplify
6c = 120
Divide both sides by <u>6</u>
6c/6 = 120/6
c = <u>20</u>
Answer:
<h2>
46</h2>
Step-by-step explanation:
x - age of a son three years ago
3x - age of a father three years ago
x + 3 - age of the son now
3x + 3 - age of the father now
x + 3 + 5 - age of the son in five years time
3x + 3 + 5 - age of the father in five years time
in five years time, the father will be twice as old as his son, so:
3x + 3 + 5 = 2(x + 3 + 5)
3x + 8 = 2x + 16
3x - 2x = 16 - 8
x = 8
x + 3 + 4 - age of the son in four years time
8 + 3 + 4 = 15
3x + 3 + 4 - age of the father in four years time
3×8 + 3 + 4 = 31
the sum of their ages in four years time:
15 + 31 = 46
