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2 years ago

10

Please help me find the slope of the line graphed below!

2 answers:

valentinak56 [21]2 years ago

8 0

Answer:

slope = - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 1, 0) and (x₂, y₂ ) = (0, - 3) ← 2 points on the line

m = $\frac{-3-0}{0+1}$ = $\frac{-3}{1}$ = - 3

CaHeK987 [17]2 years ago

3 0

Here it is described. Its really easy.

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FINDING AREA ON A COORDINATE PLANE

Fynjy0 [20]

Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

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marissa [1.9K]

Answer:

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Step-by-step explanation:

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2 years ago

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago

A store had 112 diet sodas. The ratio of diet sodas to regular sodas was 8:4. How many regular sodas were there?

IceJOKER [234]

Answer:

56

Step-by-step explanation:

There are two ways the answer to this question can be determined

<u><em>Method 1 : the fast method </em></u>

We know that 8 is twice 4

4 x 2 = 8

The ratio of diet soda = 8

the ratio of regular sodas = 4

Diet sodas = 112

the number of regular sodas = 112 / 2 = 56

<u><em>Method 2 : The long method </em></u>

I would first determine the total number of diet and regular sodas. Let the total number be represented by d

from the question, the following equation can be derived :

(8/12) x d = 112

divide both sides of the equation by 12/8 to determine the value of d

d = 112 x (12/8) = 168

We can now derive a value for the number of regular soda

regular sodas = ( ratio of regular sodas / total soda) x total number of sodas

(4/12) x 168 = 56

3 0

2 years ago